Question

Solve the system and find 2 solutions

Answer 1

`\begin{gathered} \begin{bmatrix}y=6x-1 \\ y=3x-1\end{bmatrix} \\ 3x-4=6x-1 \\ 3x-4+4=6x-1+4 \\ 3x=6x+3 \\ 3x-6x=6x+3-6x \\ -3x=3 \\ (-3x)/(-3)=(3)/(-3) \\ x=-1 \end{gathered}`

then

`\begin{gathered} y=3x-4 \\ y=3\cdot\: (-1)-4 \\ y=-3-4 \\ y=-7 \end{gathered}`

solution: (-1,-7)