Hello there. To solve this question, we'll have to remember some properties about rational functions.
Given the functions:
![f(x)=3x+2](https://img.qammunity.org/2023/formulas/mathematics/high-school/v0kwavaq0ymi9eorzokez7x77i9olkwuq3.png)
And
![g(x)=-2x-3](https://img.qammunity.org/2023/formulas/mathematics/college/frqrp7gmpgw7xyqfoclhhkn867pspvw7p1.png)
We have to evaluate
![\left((f)/(g)\right)(1)](https://img.qammunity.org/2023/formulas/mathematics/college/z8np6nh6o9er3lj940289ruvkl3y8vra8h.png)
For this, remember that:
![\left((f)/(g)\right)(x)=(f(x))/(g(x)),g(x)\text{ not equal to 0}](https://img.qammunity.org/2023/formulas/mathematics/college/i2mb6qushji1ykxrfkdojdn5pqkf8nzq3u.png)
The domain of this function is the entire real line, without the point x such that g(x) = 0.
In this case, we'll have
![\left((f)/(g)\right)(x)=(3x+2)/(-2x-3)](https://img.qammunity.org/2023/formulas/mathematics/college/pktmu3d15tfj9j4s8rwypu086ovuijzbhp.png)
Evaluating it at x = 1, we get
![\left((f)/(g)\right)(1)=(3\cdot1+2)/(-2\cdot1-3)=(3+2)/(-2-3)=(5)/(-5)=-1](https://img.qammunity.org/2023/formulas/mathematics/college/9g69muq4izovej99a5g9p9ydlch7r10au2.png)
This is the value we've been looking for.