Given:
Mass of crate = 15.0 kg
Initial speed = 1.50 m/s
Pulling force = 250 N
θ = 35.0 degrees with the horizontal
coefficient of friction = 0.400
Distance pulled = 8.00 m
Let's first draw the free body diagram below.
Let's solve for the following:
• (5) Determine the work done by the pulling force.
To find the work done by the pulling force, we have:
Work done = Force x distance
= 250 x 8.00
= 2000J
• (6) Determine the work done by the force of gravity.
Apply the formula:
Work done = Fg x S = mgS
Where S is the distance.
g is the acceleration due ot gravity = 9.8 m/s²
We have:
Work done = 15.0 x 9.8 x 8.00 = 1176 J
• (7) Determine the work done by the normal force.
Apply the formula:
W = Fn x S = (mgS)cosθ
W = 1176cos35
W = 963.32 J
ROunding to 3 significant figures = 963 J
• (8) Determine the normal force on the object .
APply the formula:
R = mgcosθ
R = 15.0 x 9.8 x cos35 = 120.4 N
Round to 3 significant figures = 120 N
• (9)Determine the work done by friction
To find the work done bu