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Graph the line that contains the point P and has slope m. Find the point-slope form of the equation of the line.

Graph the line that contains the point P and has slope m. Find the point-slope form-example-1
User Admirko
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Given point p and slope m, below


\begin{gathered} P(1,3) \\ m=(-3)/(4) \end{gathered}

The formula for finding point slope point of a straight-line graph is given below


\begin{gathered} (y-y_1)/(x-x_1)=m \\ \text{where} \\ (x_1,y_1)is\text{ the point given} \end{gathered}
x_1=1,y_1=3,m=(-3)/(4)

Substitute the given into the formula


(y-3)/(x-1)=(-3)/(4)
\begin{gathered} \text{cross}-\text{mulyiply} \\ 4(y-3)=-3(x-1)_{} \\ 4y-12=-3x+3 \\ 4y+3x=+3+12 \\ 4y+3x=+15 \\ 4y+3x=15 \end{gathered}

The graph is as shown below:

Hence, the slope-point form of the given point and slope is 4y+3x=15

Graph the line that contains the point P and has slope m. Find the point-slope form-example-1
Graph the line that contains the point P and has slope m. Find the point-slope form-example-2
User Kiko Fernandez
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