Question

STAZHto add notesDISTANCE & MIDPOINT Jormulac(-1.5, -6)(-10, 1), (-9, 8)Hidpoint, M(-7,-6), (0,8)Midpoint, MDistance,7Distance,BSAZ(4,0), (-5, -8)Midpoint, MA (-3.5, -7)(-3,5), (4,-9)Midpoint, MDistance,ParagraphDistance,1M(3,-18), (-5, -10)Midpoint, M(0.5,-2)(7,5), (1,9)Midpoint, MDistance,Distance,D3ZASNPENZ(-3,-9.5)(8, 13), (7,-1)Midpoint, M(-1,8)(-6, 8), (-8, 4)Midpoint, M(-0.5,-4)(3,-8), (-9, -11)Midpoint, MDistance, dDrawingDistance,2√130Distance,√197317(5,3)(8,-2), (4,5)Midpoint, M(-7,6)(12,-5), (2, 1)Midpoint, M(1, 12)(-11, 10), (-2,7)Midpoint, M(6, 1.5)(-5, 2), (4, 6)Midpoint, MDistance,3√10Distance,Distance,D145Distance,NNS(7.5, 6)(4, 10), (-7,0)L (2.5, 4.5)Midpoint, M(2,7), (8,-1)Midpoint, M(2, 13), (0, 11)Hidpoint, MDistance,Distance,Distance,Ee

Answer 1

Given:

The point is

`\begin{gathered} (-10,1) \\ \\ (-9,8) \end{gathered}`

Find-:

The midpoint of the point

Explanation-:

The midpoint formula is

`\begin{gathered} \text{ First point }=(x_1,y_1) \\ \\ \text{ Second point}=(x_2,y_2) \end{gathered}`

The midpoint is:

`\text{ Midpoint}=((x_1+x_2)/(2),(y_1+y_2)/(2))`

The points is

`\begin{gathered} (x_1,y_1)=(-10,1) \\ \\ (x_2,y_2)=(-9,8) \end{gathered}`

Midpoint is:

`\begin{gathered} \text{ Midpoint}=((-10+(-9))/(2),(1+8)/(2)) \\ \\ \text{ Midpoint}=((-19)/(2),(9)/(2)) \\ \\ \text{ Midpoint}=(-9.5,4.5) \end{gathered}`

Distance between two point

`\begin{gathered} D=√((x_2-x_1)^2+(y_2-y_1)^2) \\ \\ D=√((-9-(-10))^2+(8-1)^2) \\ \\ D=√((-9+10)^2+(7)^2) \\ \\ D=√(1+49) \\ \\ D=√(50) \\ \\ D=7.07 \end{gathered}`

The distance is 7.07