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4 votes

Answer:

16.7%

Step-by-step explanation:

The number of faces in a die = 6

Multiples of 3, {3,6} = 2


P(m\text{ultiple of 3)}=(2)/(6)

The total number of cards in a standard deck = 52

Number of red cards = 26


\begin{gathered} P(\text{red card)=}(26)/(52) \\ =(1)/(2) \end{gathered}

Therefore, the probability that the die will be a multiple of 3 and the card will be red:


\begin{gathered} =(2)/(6)*(1)/(2) \\ =0.16667 \\ =16.667\% \\ P(mult.\; of\; 3,red\; card)\approx16.7\%\text{ (to the nearest tenth)} \end{gathered}

User Nate Birkholz
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