Answer:
16.7%
Step-by-step explanation:
The number of faces in a die = 6
Multiples of 3, {3,6} = 2
![P(m\text{ultiple of 3)}=(2)/(6)](https://img.qammunity.org/2023/formulas/mathematics/high-school/v0il03mhx3j9531lk0ufu8kpxcdj1w5844.png)
The total number of cards in a standard deck = 52
Number of red cards = 26
![\begin{gathered} P(\text{red card)=}(26)/(52) \\ =(1)/(2) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/ax9um95apqlquxcbi6l7r3ojayxymz6ja0.png)
Therefore, the probability that the die will be a multiple of 3 and the card will be red:
![\begin{gathered} =(2)/(6)*(1)/(2) \\ =0.16667 \\ =16.667\% \\ P(mult.\; of\; 3,red\; card)\approx16.7\%\text{ (to the nearest tenth)} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/is0u2zhrb1a5rmm6j2nk8qdummw0fsl8k1.png)