Question

Calculate the amount of heat (in kJ) released when 1.52 mol of hydrogen peroxide decomposes. 2H2O2(l) rightwards arrow 2H2O(l) + O2(g) + 196.4kJ

Answer 1

Step-by-step explanation:

2 H₂O₂ (l) ---> 2 H₂O (l) + O₂ (g) + 196.4 kJ

According to the coefficients of the reaction, 2 moles of H₂O₂ will decompose into 2 moles of H₂O and 1 mol of O₂. When this decomposing reaction happens, 196.4 kJ are released.

So we can say that the decomposition of 2 moles of H₂O₂ will release 196.4 kJ. We can use that ratio to find the answer to our problem.

2 moles of H₂O₂ : - 196.4 kJ (negative because the heat is released)

Q = 1.52 moles of H₂O₂ * (-196.4 kJ)/(2 moles of H₂O₂)

Q = -151 kJ

Answer: -151 kJ will be released.