To find the linear equation for this points:
(-10, 0) and (-8, 10), we will need to use the following expression to calculate the slope:
![\begin{gathered} m=(y_2-y_1)/(x_2-x_1) \\ m=(10-0)/(-8-(-10)) \\ m=(10)/(2) \\ m=5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/vpb62z6ew8bjl20x1t2wp8aorq5lfs12ev.png)
A linear equation is represented by this expression in slope-intercept form:
![\begin{gathered} y=mx+b \\ \text{where,} \\ m\text{ is the slope and b is the y-intercept.} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/nfgb9ih7zf7ao11wcc56pem81kq5t3ffnt.png)
Since we don't have the y-intercept, we can find the equation of the line by using the slope-point form:
![\begin{gathered} y-y_0=m(x-x_0) \\ y-0=5(x+10) \\ y=5x+50 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/bbybrr63jqmamskh1ivg8ajfcx1lqquhcz.png)