We are asked to evaluate functions at specif values. We will start by the function:
![f(x)=4x^2-x](https://img.qammunity.org/2023/formulas/mathematics/college/s8ailwzzkexzhlrkoe2gjq8eiqbsd0cout.png)
We have to evaluate this function at x=-4, we do so, by substituting all the x's by the value -4 in the equation for f, as follows:
![\begin{gathered} f(-4)=4(-4)^2-(-4) \\ \text{ }=4(16)+4 \\ \text{ = 64+}4 \\ \text{ =68} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/5ka8pc4negiguow41yqawmezyjjl52401v.png)
Therefore the answer for the first box is 68
Now we will do the second evaluation, this time we are asked to find g(6) where the function g is given by
![g(x)=-2x-1](https://img.qammunity.org/2023/formulas/mathematics/college/45ms2lqloaxgw2hai314dhfqahtj0upmby.png)
Substituting all the x by the value 6, we find
![\begin{gathered} f(6)=-2(6)-1 \\ =-12-1 \\ =-13 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/fy23ke6mzi53qio9jrfaiz2zcuvadcv7yj.png)
Therefore, the answer for the second box is -13