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In an experiment, 5.00 g of copper metal reacts completely with 2.51 g of oxygen gas. Whatis the empirical formula for the compound that is produced?

In an experiment, 5.00 g of copper metal reacts completely with 2.51 g of oxygen gas-example-1
User Krauss
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The empirical formula is the simplest way to represent a compound. It tells us what the relationship is with respect to the number of atoms between one element and another. To find the empirical formula in this case, we must first calculate the moles that react in the experiment. The number of moles will be found by dividing the given grams by the molar mass of the compound.

Molar mass Cu=63.546g/mol

Molar mass O2=31.998g/mol

Let's see then how many moles react:


molCu=5.00gCu*(1molCu)/(63.546gCu)=0.08molCu
molO=2.51gO_2*(1molO_2)/(31.998O_2)=0.08molO_2

We see that the amount in moles of both compounds are equal. Therefore, the relationship is 1 to 1, that is, for each mole of metallic copper, one mole of gaseous oxygen reacts. So, the produced compound of this reaction will have the following empirical formula:


CuO_2

User Gui Ambros
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