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Write the equation of a line in slope intercept form that is parallel to the line y = 1/2x +3 and passes through the point (-3,5)

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\begin{gathered} \text{The equation of line is,} \\ y=(1)/(2)x+3 \\ \text{Compare the given equation with equation of line}\Rightarrow y=mx+b \\ So,\text{ slope}\Rightarrow m=(1)/(2) \\ \text{Now, the given point is }\Rightarrow(-3,5) \\ \text{The equation in slope-intercept form is,} \\ y-y_1=m(x-x_1) \\ y-5=(1)/(2)(x+3) \\ 2y-10=x+3 \\ 2y=x+13 \\ y=(1)/(2)x+(13)/(2) \end{gathered}

User Harry Aung
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