Question

Which equation is perpendicular to y= 4/7x + 6 and passes through (0,-2) ?

Answer 1

A perpendicular equation to a line equation, has the reciprocal and opposite slope

We have:

`y=(4)/(7)x+6`

So the new equation will have the slope -7/4:

`y_p=-(7)/(4)x+b`

b is the intercept, the point where the line crosses the y-axis. We can find the intercept using the point (0,-2). We replace x = 0 and y = -2 into the equation above and we have that b = -2.

The equation is:

`y_p=-(7)/(4)x-2`