Given a line l, if the following points
![\lbrace(x_1,y_1),(x_2,y_2)\rbrace](https://img.qammunity.org/2023/formulas/mathematics/college/e2e0u6w66wbye0pbivtdv08hhytlqwe6nl.png)
belongs to the line l, the slope m of this line is given by the following formula
![m=(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/78uaqhwt0aws3qfwxigaftpihnmb1gzxtp.png)
Using this formula in our problem, we have
![m=((-7)-(-1))/((6)-(4))=(-7+1)/(6-4)=(-6)/(2)=-3](https://img.qammunity.org/2023/formulas/mathematics/college/bqmevny3kcl6mduchcez0plx0k2uy7y1c9.png)
The slope of our line is - 3.
The slope intercept form is
![y=mx+b](https://img.qammunity.org/2023/formulas/mathematics/high-school/smsb8cbft03lwblmi49nf2l6jby2ofxzws.png)
where m represents the slope and b the y-intercept.
We already calculated the slope, if we substitute its value on this form and evaluate one of the points, we can solve the equation for b.
![\begin{gathered} (-1)=(-3)(4)+b \\ -1=-12+b \\ b=11 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/bbdjazronpjy0ukjxxsdrh4tp2tdi0x0nt.png)
Our line equation is
![y=-3x+11](https://img.qammunity.org/2023/formulas/mathematics/college/ggxzu9th4643hcpndpmyiokjfzc8k7u9c9.png)