Let us calculate the y-intercepts and average rate of change over the given intervals.
Function F

The y-intercept is gotten at x = 0:

The average rate of change can be calculated using the formula:

Using [0, 2] as [a, b], we have:

Therefore, we can solve to give:

Function G
The graph is given in the question.
The y-intercept is approximately -3.
The average rate of change can be calculated using the following parameters;

Therefore, we can solve to give:

CONCLUSION
The two graphs have the same y-intercept.
The average rate of change in graph g is less than f.
The correct option is OPTION B.