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GRAPH the line with slope -2 passing through the point (-4,-1)Rise over run method

User Rolige
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Step-by-step explanation

Let's assume that a certain line passes through the point (a,b) and has a slope m. Then its equation in point-slope form is:


y-b=m(x-a)

In this case we are told that the line passes through the point (-4,-1) and that its slope is -2 so we just need to take m=-2, a=-4 and b=-1 in the equation above to obtain the equation of this line:


\begin{gathered} y-(-1)=-2(x-(-4)) \\ y+1=-2(x+4)=-2x-8 \\ y=-2x-9 \end{gathered}

In order to graph it we need at least two of its points. We already have one, (-4,-1) and we can use its equation to find the other one. We can take x=-2:


\begin{gathered} y=-2\cdot(-2)-9=4-9 \\ y=-5 \end{gathered}

So the line also passes through the point (-2,-5).

Answer

Knowing that it passes through (-4,-1) and (-2,-5) we have the following graph:

GRAPH the line with slope -2 passing through the point (-4,-1)Rise over run method-example-1
User Dave Gruenewald
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