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Hey chemistry student needs 80.0 g of glycerol for an experiment. By consulting a CRC handbook of chemistry and physics, the student discovers that the density of the glycerol is 1.26 g/cm -3. Calculate the volume of the glycerol Student should pour out. Be sure you answer in the crack significant digits. Answer will be in milliliters

Hey chemistry student needs 80.0 g of glycerol for an experiment. By consulting a-example-1
User Spstanley
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1 Answer

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So,

First, remember that the density is defined as the mass of a substance per unit of volume.

We can express this definition with the following equation:


d=(m)/(v)

Where d represents the density, m the mass and v the volume.

In this problem, we're given that m=80.0g and v=1.26g/cm3. If we want to find the volume, we can write:


d=(m)/(v)\to v=(m)/(d)

So, we divide:


\frac{80g}{\frac{1.26g}{\operatorname{cm}3}}=63.49cm^3

The answer has to be given in mL, so:


63.49cm^3\cdot(1mL)/(1cm^3)=63.49mL

So, the volume is 63.49mL.

With a significant digit, the answer is 63.5 mL.

User Tomsgu
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