Question

A student uses a sample of KOH stock solution and dilutes it to a total of 120 mL. If the diluted solution is 0.60 M KOH and its original concentration was 2.25 M, what was the volume of the original sample?

Answer 1

A solution of KOH solution was made, and we are asked to find the volume of the initial solution. We will apply the following equation to find it:

`C_1V_1=C_2V_2`

C1 is the concentration of the original solution, 2.25M

V1 is the volume we have to find

C2 is the final concentration, 0.60M

V2 is the final concentration 120mL

We clear V1 and replace the known data:

`V_1=(C_2V_2)/(C_1)`
`\begin{gathered} V_1=(0.60M*120mL)/(2.25M) \\ V_1=32mL \end{gathered}`

The volume of the original sample is 32mL

Answer: 32mL