Question

32A(2, 2)(-2,-2)The distance of AB = [? ]Round to the nearest tenth.Hint: d = √(x₂ - ×1 )² + (Y2 − Y1)²X1Enter

Answer 1

Given:

Point A = ( 2, 2 )

Point B = ( -2, -2 )

Find-:

Distance between point A to point B

Explanation-:

Distance between two points is:

Let,

`\begin{gathered} \text{ First point }=(x_1,y_1) \\ \\ \text{ Second point }=(x_2,y_2) \end{gathered}`

Distance is:

`D=√((x_2-x_1)^2+(y_2-y_1)^2)`

Distance AB is

`\begin{gathered} A(x_1,y_1)=(2,2) \\ \\ B(x_2,y_2)=(-2,-2) \end{gathered}`

So, AB is:

`\begin{gathered} AB=√((x_2-x_1)^2+(y_2-y_1)^2) \\ \\ (x_1,y_1)=(2,2) \\ \\ (x_2,y_2)=(-2,-2) \\ \\ AB=√((-2-2)^2+(-2-2)^2) \\ \\ AB=√((-4)^2+(-4)^2) \\ \\ AB=√(16+16) \\ \\ AB=√(2*16) \\ \\ AB=4√(2) \\ \\ AB=5.657 \end{gathered}`