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Determinethenumberof g HClthatcanreactwith 0.750 g Al(OH)3accordingtothefollowingreactionAl(OH)₃(s)+HCl(aq)→AlCl₃(aq)+H₂O(aq)

User Eapo
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1 Answer

4 votes

Step 1 - Balancing an reading the chemical equation

The provided chemical equation is:


HCl_((aq))+Al(OH)_(3(s))\rightarrow H_2O_((aq))+AlCl_(3(aq))

This equation is not balanced yet. The first step in any stoichiometry exercise is to balance the equation:


3HCl_((aq))+Al(OH)_(3(s))\operatorname{\rightarrow}3H_2O_((aq))+AlCl_(3(aq))

The equation is now properly balanced and we can "read" it as:

3 moles of HCl react with one mole of Al(OH)3 thus producing 3 moles of water and one mole of AlCl3

As the exercise is specifically asking about the proportion between HCl and Al(OH)3, we can further simplify this statement to:

3 moles of HCl react with one mole of Al(OH)3

User Pete Becker
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