Determinethenumberof g HClthatcanreactwith 0.750 g Al(OH)3accordingtothefollowingreactionAl(OH)₃(s)+HCl(aq)→AlCl₃(aq)+H₂O(aq)

Question

asked Jan 9, 2023 148k views

1 Answer

Pete Becker · Answer 1 · 2023-01-16T05:48:50+0000

Step 1 - Balancing an reading the chemical equation

The provided chemical equation is:

$HCl_((aq))+Al(OH)_(3(s))\rightarrow H_2O_((aq))+AlCl_(3(aq))$

This equation is not balanced yet. The first step in any stoichiometry exercise is to balance the equation:

$3HCl_((aq))+Al(OH)_(3(s))\operatorname{\rightarrow}3H_2O_((aq))+AlCl_(3(aq))$

The equation is now properly balanced and we can "read" it as:

3 moles of HCl react with one mole of Al(OH)3 thus producing 3 moles of water and one mole of AlCl3

As the exercise is specifically asking about the proportion between HCl and Al(OH)3, we can further simplify this statement to:

3 moles of HCl react with one mole of Al(OH)3