Question

How many moles of sodium nitrate are in 2.0L of a 0.50M solution

Answer 1

INFORMATION:

We know that:

- there are 2.0L of solution

- the solution has a molarity of 0.50M

And we must find the number of moles of the solute (sodium nitrate)

STEP BY STEP EXPLANATION:

To find it, we need to use the formula of the molarity

`Molarity=\frac{moles\text{ of solute}}{litres\text{ of solution}}`

Is given that,

- Molarity = 0.50M = 0.50 mol/L

- litres of solution = 2.0L

Now, replacing in the formula

`0.50(mol)/(L)=\frac{moles\text{ of solute}}{2.0L}`

Finally, solving for the moles of solute

`\begin{gathered} 0.50(mol)/(L)\cdot2.0L=moles\text{ of solute} \\ 1.0mol=moles\text{ of solute} \\ moles\text{ of solute}=1.0mol \end{gathered}`

ANSWER:

There is 1.0mol of sodium nitrate in 2.0L of a 0.50M solution