Question

For ABC, let a = 28, b = 47, and,.........

Answer 1

58

Explanation:

Answer 2

As given by the question

There are given that the value of sides and angle:

`a=28,\text{ b=47, and m}\angle C=98^(\circ)`

Now,

From the cosine rule:

`c^2=b^2+a^2-2ab\cos C`

Then,

`c^2=47^2+28^2-2*28*47\cos 98`

Then,

`\begin{gathered} c^2=47^2+28^2-2*28*47\cos 98 \\ c^2=2209+784-2632*\cos 98^(\circ) \\ c^2=2209+784+366.30 \\ c^2=3359.3 \end{gathered}`

Then,

`\begin{gathered} c^2=3359.3 \\ c^{}=√(3359.3) \\ c=57.959 \\ c=58 \end{gathered}`

Hence, the value of c is 58.