Question

PLEASEEE HELP FAST!!!

Answer 1

The form is

`\\ \tt\longmapsto f(x)=Asin(B(x+c))+D`

where

• A=Amplitude
• Period=2π/B
• Phase shift=c
• Vertical shift=D

Now compare to our given function

• Amplitude=-1/3
• Period=2π/3
• phase shift=c=π
• Vertical shift=-3

Answer 2

Amplitude = 1/2

Period =
`\frac23 \pi`

Phase shift =
`\pi` (left)

Vertical shift =
`-3`

Explanation:

`f(x)=-\frac12cos(3(x+\pi))-3`

`y = A sin(B(x + C)) + D`

Amplitude is A = 1/2

Period is
`\frac2B \pi` =
`\frac23 \pi`

Phase shift is C=
`\pi` (left)

Vertical shift is D =
`-3`