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4 votes
Hello! I got this one wrong and need to know how to properly do this type of problem in the future.

Hello! I got this one wrong and need to know how to properly do this type of problem-example-1

2 Answers

4 votes

Answer: 100ft

If
t = 2 seconds
h = 20 ft
v = 72 ft/s

Then the answer from the question has to be

100ft

7 votes

Given:


y=-16t^2+vt+h

Let's find the height of the ball, y, when:

t = 2 seconds

h = 20 ft

v = 72 ft/s

Plug in the values in the equation and solve for y.

We have:


\begin{gathered} y=-16(2)^2+72(2)+20 \\ \\ y=-16(4)+144+20 \\ \\ y=-64+144+20 \\ \\ y=100 \end{gathered}

Therefore, the height of the ball is 100 ft.

ANSWER:

100 ft.

User Brendon Randall
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