Question

Hello! I got this one wrong and need to know how to properly do this type of problem in the future.

Answer 1

Answer: 100ft

If
t = 2 seconds
h = 20 ft
v = 72 ft/s

Then the answer from the question has to be

100ft

Answer 2

Given:

`y=-16t^2+vt+h`

Let's find the height of the ball, y, when:

t = 2 seconds

h = 20 ft

v = 72 ft/s

Plug in the values in the equation and solve for y.

We have:

`\begin{gathered} y=-16(2)^2+72(2)+20 \\ \\ y=-16(4)+144+20 \\ \\ y=-64+144+20 \\ \\ y=100 \end{gathered}`

Therefore, the height of the ball is 100 ft.

ANSWER:

100 ft.