Question

An elevator motor in a high-rise building can do 3500 kJ of work in 5 min. Find the power developed by the motor. Explain if you can plz

Answer 1

P = 11666.6 W

Step-by-step explanation:

Given that,

Work done by the motor, W = 3500 kJ

Time, t = 5 min = 300 s

We need to find the power developed by the motor. Power developed is given by :

`P=(E)/(t)\\\\P=(3500* 10^3)/(300)\\\\P=11666.7\ W`

So, the required power is 11666.6 W.