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If gas a volume of 509 liters and pressure of 697 atm and the pressure to 789 atm what is the new volume ?

If gas a volume of 509 liters and pressure of 697 atm and the pressure to 789 atm-example-1

1 Answer

1 vote

Answer:

449.65L

Explanations:

2) According to the Boyle's law, the pressure of a given mass of gas is inversely proportional to its volume provided that the temperature is constant.


\begin{gathered} P\alpha(1)/(V) \\ P=(k)/(V) \\ k=P_1V_1=P_2V_2 \\ \end{gathered}

P1 and P2 are the initial and final pressures

V1 and V2 are the initial and final volumes

Given the following parameters

V1 = 509litres

P1 = 697atm

P2 = 789atm

Substitute to determine the new volume V2


\begin{gathered} V_2=(P_1V_1)/(P_2) \\ V_2=(697*509)/(789) \\ V_2=(354773)/(789) \\ V_2=449.65L \end{gathered}

Hence the new volume of the gas is approximately 449.65L

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