Question

How much is (OH-) when (H+) = 0.001m?a. 1x10^-3mb. 1x10^3mc. 1x10^-11md. 1x 10^11m

Answer 1

We know that the product of the concentrations of OH and H ions represents a constant.

`\lbrack H^+\rbrack\lbrack OH^-\rbrack=1*10^(-14)_{}`

Then, we solve for OH concentration.

`\lbrack OH^-\rbrack=(1*10^(-14))/(0.001)=1*10^(-11)M`

Therefore, the concentration of hydroxide is C. 1x10^-11 M.