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Find the area of the triangle 10.6 m 4.6 m 6.6 m 5 m 4 m

User Unoti
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The area of the figure can be found by dividing the figure into 2 triangles and 1 rectangle

using the pythagorean find the base of the triangle to the right


\begin{gathered} 5^2=4.6^2+x^2 \\ x=\sqrt[]{5^2-4.6^2} \\ x=\sqrt[]{25-21.16} \\ x=\sqrt[]{3.84} \\ x=1.959m\approx2.0m \end{gathered}

find the base of the the triangle to the left


\begin{gathered} y=10.6-2-4 \\ y=4.6 \end{gathered}

find the area for ach figure


\begin{gathered} A_1=4.6\cdot(2)/(2)m^2 \\ A_1=4.6m^2 \\ A_2=4\cdot4.6m^2 \\ A_2=18.4m^2 \\ A_3=4.6\cdot(4.6)/(2)m^2 \\ A_3=10.58m^2 \end{gathered}

add the three areas together


\begin{gathered} A=(10.58+4.6+18.4)m^2 \\ A\approx33.58m^2 \end{gathered}

User Jake Bruun
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