Question

mmonia can be prepared by reacting nitrogen gas, taken from the atmosphere, with hydrogen gas.N2 (g) + 3 H2 (g) → 2 NH3 (g)When 75 g of nitrogen reacts with sufficient hydrogen, the theoretical yield is ammonia is 9.10 g. If 1.72 g of ammonia is obtained by experiment, what is the percentage yield of the reaction?Select one:a.529%b.2.29%c.18.9%d.12.1%

Answer 1

Chemistry => Stoichiometry => Theoretical Yield and Percentage Yield

The percentage yield corresponds to the percentage that is actually obtained compared to what is theoretically expected.

We can define it by the following equation:

`PercentageYield=(ActualYield)/(TheoreticalYield)*100\%`

They already give us the theoretical and actual yield, so we can replace the known data in the equation.

Actual Yield = 1.72g of NH3

Theoretical Yield = 9.10g of NH3

So, the percentage yield will be:

`\begin{gathered} PercentageYield=(1.72g)/(9.10g)*100\% \\ \\ PercentageYield=18.9\% \end{gathered}`

Therefore the answer will be: c. 18.9%