Question

All numbers that are evenly divisible by both 6 and 14 are also divisible by which of the following numbers? A. 8B. 12C. 21D. 28

Answer 1

`\text{The number is }21`

Here, we want to get the number which divides all numbers that are evenly divisible by 6 and 14

Looking at both numbers, we can see that at any point in time we can have;

`\begin{gathered} 6\text{ = 2}*3 \\ 14=2*7 \end{gathered}`

we can have 2 in two times and 3 in a single time and 7 in a single time. All we have to do is to multiply 3 and 7 which gives 21 (we simply cancel out the two on both ends)

This mean at any point in time, every number evenly divisible by 6 and 14 is also evenly divisble by 21