Question A:
A linear equation in slope-intercept form is of the form:
![\begin{gathered} y=mx+c \\ \text{where,} \\ m=\text{slope of the linear graph} \\ c=y-\text{intercept of the linear graph.} \\ \\ \\ \text{For our question, }y\text{ represents the water level of the river in feet. }x\text{ represents the number of days, }m\text{ represents} \\ \text{the rate of change of the level of water per day, while }c\text{ is the initial level of water.} \end{gathered}]()
From the question, we can conclude that:
m = -0.5 (the slope is negative because the water level is reducing)
c = 34.
Thus, the equation is given as:
![\begin{gathered} y=-0.5x+34 \\ \text{where,} \\ x=\text{ number of days} \\ y=\text{level of water in feet} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/bfpqtoj6ebdzo4je6duug5ancar3vz47qb.png)
Question B:
![\begin{gathered} \text{After 38 days, we need to find the level of water.} \\ \text{This means that:} \\ x=38\text{ and we need to find the value of }y \\ \\ y=-0.5(38)+34 \\ y=-19+34 \\ \therefore y=15\text{feet} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/1m9taaflme11a4f44cv067i35jxyami5n8.png)
Thus, the water level after 38 days is 15 feet
Question C:
![\begin{gathered} \text{ We need the number of days when the water level is 26 feet.} \\ \text{This means that:} \\ y=26,x=? \\ \\ \text{Thus, we can say:} \\ 26=-0.5x+34 \\ \text{Subtract 34 from both sides} \\ 26-34=-0.5x \\ -8=-0.5x \\ \text{Divide both sides by }-0.5 \\ -(0.5x)/(-0.5)=-(8)/(-0.5) \\ \\ x=16 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/hbtortx1r2rxwtb9cjz98m54lj4usyu7km.png)
16 days have elapsed when the water level is at 26 feet
Answer
Question A:
The equation is:
![y=-0.5x+34](https://img.qammunity.org/2023/formulas/mathematics/college/3jlhms8zoub0aisxmaxv0rrtvuar0dusa8.png)
Question B:
The water level after 38 days is 15 feet
Question C:
16 days have elapsed when the water level is at 26 feet