Question

Suppose a normal distribution has a mean of 79 and a standard deviation of 7. What is P(x ≤ 93)?A. 0.975B. 0.025C. 0.84D. 0.16

Answer 1

A. 0.975

Step-by-step explanation:

To determine P(x ≤ 93), we first find the z-score.

`\begin{gathered} Z-\text{Score}=(X-\mu)/(\sigma) \\ =(93-79)/(7) \\ =(14)/(7) \\ =2 \end{gathered}`

Therefore:

`P\begin{pmatrix}x\leqslant93\end{pmatrix}=0.975`