Question

A horizontal force of 20 N just starts to move a box with weight80 N. Find the value of coefficient of static friction.

Answer 1

The static friction formula is

`\begin{gathered} F_s=\mu_sN \\ \mu_s=(F_s)/(mg) \end{gathered}`

As you can observe, the normal force is equal to the weight force.

`\mu_s=(20N)/(80N)=0.25`

Therefore, the value of the coefficient of static friction is 0.25.