Question

I need help with problem 6 on my Algebra 1 homework

Answer 1

The question is given to be:

`2q^2-(4)/(5)\mleft(5q-6\mright)+4q^2`

Step 1: Expand the middle term using the Distributive Property given as:

`a(b+c)=a\cdot b+a\cdot c`

Therefore, we get

`\begin{gathered} -(4)/(5)(5q-6)=-(4)/(5)(5q)-(4)/(5)(-6) \\ =-4q+(24)/(5) \end{gathered}`

Thus, the expression becomes:

`\Rightarrow2q^2-4q+(24)/(5)+4q^2`

Step 2: Collect the like terms together.

`\Rightarrow2q^2+4q^2-4q+(24)/(5)`

Step 3: Add and subtract as necessary.

`\Rightarrow6q^2-4q+(24)/(5)`

Step 4: Combine all terms into a single fraction. The lowest common multiple of the 3 terms is 5; this will be the denominator.

`\Rightarrow(5(6q^2)-5(4q)+24)/(5)`

Therefore, we get the answer to be:

`\Rightarrow(30q^2-20q+24)/(5)`