1 Answer

Paul Prewett · Answer 1 · 2023-12-14T05:50:21+0000

The question is given to be:

$2q^2-(4)/(5)\mleft(5q-6\mright)+4q^2$

Step 1: Expand the middle term using the Distributive Property given as:

$a(b+c)=a\cdot b+a\cdot c$

Therefore, we get

$\begin{gathered} -(4)/(5)(5q-6)=-(4)/(5)(5q)-(4)/(5)(-6) \\ =-4q+(24)/(5) \end{gathered}$

Thus, the expression becomes:

$\Rightarrow2q^2-4q+(24)/(5)+4q^2$

Step 2: Collect the like terms together.

$\Rightarrow2q^2+4q^2-4q+(24)/(5)$

Step 3: Add and subtract as necessary.

$\Rightarrow6q^2-4q+(24)/(5)$

Step 4: Combine all terms into a single fraction. The lowest common multiple of the 3 terms is 5; this will be the denominator.

$\Rightarrow(5(6q^2)-5(4q)+24)/(5)$

Therefore, we get the answer to be:

$\Rightarrow(30q^2-20q+24)/(5)$

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