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How long will it take for an investment to triple, if interest is compounded continuously at 3%?

User Gary Green
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5 votes

Answer:

37 years

Explanation:

When interest is being compounded continuously, we use the below compound interest formula;


A=Pe^(rt)

where A = future value of the investment

P = principal amount (initial investment)

r = interest rate in decimal

t = time in years

From the question, we're told that the future value(A) of the initial investment amount(P) will be triple, so we have that A = 3P.

Also, we're given an interest rate of 3%, so r = 3/100 = 0.03

Let's substitute these values into our formula;


3P=Pe^(0.03t)

We'll follow the below steps to solve for t;

Step 1: Divide both sides by P;


\begin{gathered} (3P)/(P)=(Pe^(0.03t))/(P)^{} \\ 3=e^(0.03t) \end{gathered}

Step 2: We'll now take the natural logarithm of both sides;


\begin{gathered} \ln 3=\ln (e^(0.03t)) \\ \ln 3=0.03t\ln e \\ \text{Note that ln e = 1} \\ \ln 3=0.03t \end{gathered}

Step 3: Divide both sides by 0.03;


\begin{gathered} t=(\ln 3)/(0.03) \\ t=36.6 \\ t\approx37\text{ years} \end{gathered}

User James Crosswell
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