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Use elimination to solve the system of equations. - 3x – 2y = -5 7x + y = 1

User Sandrine
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Given the following system of equations:


\begin{cases}-3x-2y=-5 \\ 7x+y=1\end{cases}

notice that we can multiply by 2 the second equation to get:


2\cdot(7x+y=1)=14x+2y=2

then, we can add both equations to get the following:


\begin{gathered} 14x+2y=2 \\ -3x-2y=-5 \\ ---------- \\ 11x=-3 \\ \Rightarrow x=-(3)/(11) \end{gathered}

Now that we have that x=-3/11, we can use this value to find y on the original second equation:


\begin{gathered} 7(-(3)/(11))+y=1 \\ \Rightarrow-(21)/(11)+y=1 \\ \Rightarrow y=1+(21)/(11)=(11)/(11)+(21)/(11)=(32)/(11) \\ y=(32)/(11) \end{gathered}

therefore, the solution of the syste is (-3/11,32/11)

User Matias Haeussler
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