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"Is it possible to find nonzero whole numbers m and n such that 11^m = 13^n? Explain."

1 Answer

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Given the following expression:


11^m=13^n

Solving :


\sqrt[n]{11^m}=\sqrt[n]{13^n}
\sqrt[n]{11^m}=13

We can write the root in the following way:


\sqrt[n]{11^m}=11^{(m)/(n)}

Therefore:


11^{(m)/(n)}=13

If m>n :


11^{(m)/(n)}>11

If m
11^{(m)/(n)}<11Therefore, m have to be greater than n.

Finally: if m and n are integers:


11^{(m)/(n)}=11^{(3)/(2)}=36.48

To get a value equal to 13, n has to be close to m, otherwise the number will be very large.

In this case: (Using the same numbers of the example):


11^{(m)/(n)}=11^{(3)/(2.8)}=13.0550

Answer: It is impossible to find non-zero integer numbers, because m or n have to be a rational number.

User Wesley Egbertsen
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