Answer:
4.98 moles of H₂O
Step-by-step explanation:
The balanced chemical equation for the combustion of propane is:
C₃H₈ (g) + 5 O₂ (g) ⟶ 3 CO₂ (g) + 4 H₂O (g)
That means that 1 mol of propane (C₃H₈) produces 4 moles of water (H₂O).
We know that 1 mol is equal to 6.022 x 10²³ molecules. So, we convert the molecules of propane to moles as follows:
7.50 x 10²³ molecules C₃H₈ x 1 mol/6.022 x 10²³ molecules = 1.245 mol C₃H₈
Now, we use the stoichiometric ratio 4 mol H₂O/1 mol C₃H₈ derived from the chemical equation to calculate the moles of water produced:
1.245 mol C₃H₈ x 4 mol H₂O/1 mol C₃H₈ = 4.98 mol H₂O