1) Let's solve that system by elimination. We'll eliminate the x terms firstly:
Since the LMC, between 3 and 2 is 6 let's multiply the first and the second equation to get 6x
-3x-7y=-3 x -2
-2x+5y=-2 x 3
6x +14y= 6
-6x+15y=-6
-------------------------
0 + 29y = 0
y= 0
2) Now let's plug into one of those equations, usually the simpler one, that value for y. To find out the x.
-2x +5y=-2
-2x +5(0) =-2
-2x= -2
2x=2 Divide both sides by 2
x=1
3) So the solution for this system is (1,0).