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A race car rounds a curve at 54 m/s. The radius of the curve is 441 m, and the car’s mass is 610 kg. (Assume that the car’s speed remains constant. Take the radially inward direction to be positive) The car’s acceleration is 6.61 m/s2. What is the value of this acceleration in terms of "g"?

A race car rounds a curve at 54 m/s. The radius of the curve is 441 m, and the car-example-1

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Given:

The speed of the car is: v = 54 m/s

The radius of the curve is: r = 441 m

The mass of the car is: m = 640 kg

The acceleration of the car is: a = 6.61 m/a^2

To find:

The value of acceleration in terms of g (acceleration due to gravity).

Step-by-step explanation:

The car has an acceleration of 6.61 m/s^2.

The acceleration of 6.61 m/s^2 can be written in terms of g (acceleration due to gravity) as:


a_g=\frac{a}{9.8\text{ m/s}^2}* g=\frac{6.61\text{ m/s}^2}{9.8\text{ m/s}^2}* g=0.675g

Final answer:

The acceleration of the car in terms of g (acceleration due to gravity) is 0.675g.

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