Question

Find the number of terms (n) where the sum of a geometric series for those terms is 3411+4+16+64

Answer 1

Given the gemometric sum:

1 + 4 + 16 + 64...

where r = 4;

The sum of the first four terms is equal to:

1 + 4 + 16 + 64 = 85

Now, the sum of the first five terms is equal to:

1 + 4 + 16 + 64 + (64 x 4) =

1 + 4 + 16 + 64 + 256 = 341

ANSWER

n = 5