Assuming number 2 is related,
Let's identify first AngleEBA since AngleEAB = 38 Degrees
Let,
x = AngleEAB = AngleEAD = AngleECD = AngleECB; 4x since the angles are equal
y = AngleEBA = AngleEBC = AngleEDC = AngleEDA; 4y since the angles are equal
Sum of all angles inside the Rhombus = 360 Degrees
We get,
(AngleABE x 4) + (AngleEAB x 4) = 360 Degrees.
4x + 4y = 360
4x + 4(38) = 360
4x = 360 - 152
x = AngleEBA = 52 Degrees
Let's identify AngleAEB:
AngleAEB = 180 - (AngleEAB + AngleEBA) = 180 - (38 + 52)
AngleAEB = 90 Degrees
It's a right triangle,
thus, we could apply the Pythagorean theorem to get the length of AB.
Let, a = 5; b = 12; c = AB
a^2 + b^2 = c^2
(5)^2 + (12)^2 = c^2
25 + 144 = c^2
c = Square root of 169
c = AB = 13
Since the rhombus is a square, all sides are equal.
Perimeter of ABCD = 4s
Perimeter of ABCD = 4 x 13
Perimeter of ABCD = 52