Question

HELP how do you do this equation

Answer 1

So, we want to find the slope of the line that goes through the points (-11 , -13) and (-8,3).

For this, remember that:

Given two points that lie on a line:

`\begin{gathered} (x_1,y_1) \\ (x_2,y_2) \end{gathered}`

The slope of the line that goes through these points can be found if we apply the following formula:

`m=(y_2-y_1)/(x_2-x_1)`

In our question, we are given that:

`\begin{gathered} (x_1,y_1)=(-11,-13) \\ (x_2,y_2)=(-8,3) \end{gathered}`

So,

`\begin{gathered} x_1=-11 \\ y_1=-13 \\ x_2=-8 \\ y_2=3 \end{gathered}`

The only thing we have to do now, is to replace. So,

`m=(3-(-13))/(-8-(-11))=(3+13)/(-8+11)=(16)/(3)`

Therefore, the slope of the line is 16/3