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X^2+y^2=10 y=3How would I find the points this intersects using the quadratic formula?

1 Answer

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x^2 + y^2 = 10

y = 3

The above equation represent the equation of a circle

x^2 + y^2 = r^2 --------- at the origin

(x - a)^2 + (y - b)^2 = r^2 -------- at points a and b

since y = 3

x = 0

r^2 = 10

we can find r by finding the squareroot of both sides


\begin{gathered} \sqrt[]{r^2}\text{ = }\sqrt[]{10} \\ \text{square will cancelled out squareroot} \\ \text{Then r becomes }\sqrt[]{10} \\ r\text{ = }\sqrt[]{10} \end{gathered}

(0 , 3) and r = root of 10

User Martin Kenny
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