x^2 + y^2 = 10
y = 3
The above equation represent the equation of a circle
x^2 + y^2 = r^2 --------- at the origin
(x - a)^2 + (y - b)^2 = r^2 -------- at points a and b
since y = 3
x = 0
r^2 = 10
we can find r by finding the squareroot of both sides
![\begin{gathered} \sqrt[]{r^2}\text{ = }\sqrt[]{10} \\ \text{square will cancelled out squareroot} \\ \text{Then r becomes }\sqrt[]{10} \\ r\text{ = }\sqrt[]{10} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/be8bvlf80mtix35jiclhpllyb90chii3sa.png)
(0 , 3) and r = root of 10