35.2k views
3 votes
Find the Discriminant and describe the number and type of solutions of the equations. 1) 4x^2 + 8x + 4 =0

1 Answer

6 votes

Given:


4x^2+8x+4=0​

To find the discriminant, use the formula:


\Delta=b^2-4ac

Where a = 4, b = 8, c = 4

Thus, we have:


\begin{gathered} \Delta=8^2-4(4)(4) \\ \\ \Delta=64-64\text{ =0} \end{gathered}

The discriminant is = 0

To find the number of solutions, since the disriminant is zero, we have two real and identical roots.

ANSWER:

Discriminant = 0

Number of roots = 2 real and identical roots

User Nimit Parekh
by
8.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.