Question

Find the Discriminant and describe the number and type of solutions of the equations. 1) 4x^2 + 8x + 4 =0

Answer 1

Given:

`4x^2+8x+4=0​`

To find the discriminant, use the formula:

`\Delta=b^2-4ac`

Where a = 4, b = 8, c = 4

Thus, we have:

`\begin{gathered} \Delta=8^2-4(4)(4) \\ \\ \Delta=64-64\text{ =0} \end{gathered}`

The discriminant is = 0

To find the number of solutions, since the disriminant is zero, we have two real and identical roots.

ANSWER:

Discriminant = 0

Number of roots = 2 real and identical roots