Question

Referring to the figure, find the sine of angel R. Reduce the answer to the lowest terms.

Answer 1

Recall the sine function where

`\sin \theta=\frac{\text{opposite}}{\text{hypotenuse}}`

Relative to ∠R, the opposite side is 12 units in length, and the hypotenuse is 15 units.

The sine of ∠R is

`\begin{gathered} \sin R=\frac{\text{opposite}}{\text{hypotenuse}} \\ \sin R=(12)/(15) \\ \\ \text{Reducing to lowest terms, the sine of }\angle R\text{ is} \\ \sin R=(4)/(5) \end{gathered}`