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The probability of buying a movie ticket with a popcorn coupon is 0.717. If you buy 21 movie tickets, what is the probabilitythat exactly 14 of the tickets have popcorn coupons? (Round your answer to 3 decimal places if necessary.)

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When a ticket is bought, there are 2 outcomes. It's either it comes with a popcorn or not. These outcomes are independent. This means that it is a binomial distribution. We would apply the binomial ditribution formula which is expressed as

P(x) = nCx * p^x * q^(n - x)

where

n is the number of trials

x is the number of successess

p is the probability of success

q is the probability of failure

A success in this case is the outcome of buying a ticket that has popcorn coupons. Thus,

p = 0.717

q = 1 - p = 1 - 0.717 = 0.283

n = 21

x = 14

We want to find P(x = 14)

Thus,

P(x = 14) = 21C14 * 0.717^14 * 0.283^(21 - 14)

P(x = 14) = 116280 0* 0.717^14 * 0.2837

P(x = 14) = 0.160

the probabilitythat exactly 14 of the tickets have popcorn coupons is 0.160)

User Liam Sorsby
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